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IP Address Questions

November 21st, 2018 Go to comments

Question 1


IP multicast is a bandwidth-conserving technology that reduces traffic by simultaneously delivering a single stream of information to potentially thousands of corporate recipients and homes.

IP multicast delivers application source traffic to multiple receivers without burdening the source or the receivers while using a minimum of network bandwidth.

Reference: http://www.cisco.com/c/en/us/td/docs/ios/solutions_docs/ip_multicast/White_papers/mcst_ovr.html

Question 2

Question 3

Question 4


In order to send traffic to multiple devices (not all) across different subnets we need to use multicast addresses, which are in the range through -> D is correct.

Question 5


The RFC 1518 is Classless Interdomain Routing (CIDR), which is created to save the IPv4 addresses because we can now assign IP addresses classless. Therefore, instead of assigning the whole block of a class B or C address, now smaller blocks of a class can be assigned. For example, instead of assigning a whole block of, a smaller block, like or, can be assigned.

The RFC 1918 is Address Allocation for Private Internets, which reserves IP addresses for private and internal use. These addresses can be used for networks that do not need to connect to the Internet.

Therefore the RFC 1918 is the best choice to “alleviate the depletion of IPv4 public addresses”.

Question 6


Only three connection types are commonly known and used in Internet Protocol version four (IPv4) networks: unicast, multicast and broadcast. A fourth connection type, Anycast, was unknown until IPv6 made it a standard connection type. Anycast is not standardized in IPv4 but can be emulated. IPv4 Anycast addressing is a good solution to provide localization for services and servers in order to obtain robustness, redundancy and resiliency.

The basic idea of Anycast is very simple: multiple servers, which share the same IP address, host the same service. The routing infrastructure sends IP packets to the nearest server (according to the metric of the routing protocol used). The major benefits of employing Anycast in IPv4 are improved latency times, server load balancing, and improved security.

Reference: http://citeseerx.ist.psu.edu/viewdoc/download?doi=

Question 7


Usually using private IPv4 addresses in a organization is free so surely they are less costly than public IP addresses which you have to buy -> B is correct.

Also we can use private IPv4 addresses to devices that do not need to connect to the Internet because Internet requires public IPv4 addresses -> C is correct.

Answer D is not correct as we still need to use NAT policies to limit which private IPv4 addresses in our company can access our resources.

Question 8

Question 9


This is a tricky question if you don’t have a close look on the network. The first octet is 191, not 192 so it belongs to class B, not class C.

Question 10

Question 11

Question 12


The Internet authorities have reserved the multicast address range of 01:00:5E:00:00:00 to 01:00:5E:7F:FF:FF for Ethernet and Fiber Distributed Data Interface (FDDI) media access control (MAC) addresses.

Comments (24) Comments
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  1. Clear
    September 30th, 2018
  2. Yusuf UYANIK
    October 17th, 2018

    Q1 is answer -D-E

  3. cris
    November 25th, 2018

    question 10

    Intra network (LOCAL AREA NETWORK)
    applications with Internet

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    December 6th, 2018

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    April 17th, 2019

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    April 23rd, 2019

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    September 15th, 2019

    Can someone work me through the math on this problem from the Cisco CCNA

    6. A fellow engineer tells you to configure the DHCP server to lease the last 350 usable IP addresses in subnet
    Which of the following IP addresses could be leased as a result of your new configuration?
    a –
    b – 10.1.4-250
    c –
    d –
    e –

  15. Anonymous
    September 15th, 2019

    A class B network needs to be subnetted such that is supports 300 subnets and 60 host/subnet
    (select two answers)

    A. Network = 16. subnet = 8, host =8
    B. Network = 16. subnet = 11, host =5
    C. Network = 16. subnet = 7, host =9
    D. Network = 16. subnet = 11, host =6
    E. Network = 16. subnet = 10, host =6

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